Coding Tips -- Compare The Version Numbers Between Two Releases

Given two version numbers, How to check which release is newer ? For example:

1.1 is newer than 1.0 (1.1 > 1.0);

1.0.0 is equal to 1.0(1.0.0 = 1.0);

0.9 is older than 1.0(0.9 < 1.0).

Function implement is as below:

/**
* Compare two versions.
* @param string $newVersion
* @param string $oldVersion
* @return int. 1 represents '>',0 represents '=',-1 represents '<'
*/
function versionCompare($newVersion,$oldVersion)
{
    $newArray = explode(".",$newVersion);
    $oldArray = explode(".",$oldVersion);
    do{
        $v1 = array_shift($newArray);
        $v2 = array_shift($oldArray);
        if($v1 == NULL){
            $v1 = 0;
        }

        if($v2 == NULL){
            $v2 = 0;
        }
        if($v1 > $v2){
            return 1;
        }else if($v1 < $v2){
            return -1;
        }
    }while(count($newArray) > 0 || count($oldArray) > 0);

    return 0;
}

Test Cases is as below:

var_dump(versionCompare('',''));		// =	
var_dump(versionCompare('1.0','1.0'));		// =
var_dump(versionCompare('1.1','1.0')); 		// >
var_dump(versionCompare('0.9','1.0'));		// <
var_dump(versionCompare('1.0.0','1.0'));	// =
var_dump(versionCompare('1.0.1','1.0'));	// >
var_dump(versionCompare('1.0.1','1.0.2'));	// <